Criteria under which a Dedekind domain is a PID #
This file contains some results that we can use to test wether all ideals in a Dedekind domain are principal.
Main results #
Ideal.IsPrincipal.of_finite_maximals_of_isUnit
: an invertible ideal in a commutative ring with finitely many maximal ideals, is a principal ideal.IsPrincipalIdealRing.of_finite_primes
: if a Dedekind domain has finitely many prime ideals, it is a principal ideal domain.
Let P
be a prime ideal, x ∈ P \ P²
and x ∉ Q
for all prime ideals Q ≠ P
.
Then P
is generated by x
.
An invertible fractional ideal of a commutative ring with finitely many maximal ideals is principal.
https://math.stackexchange.com/a/95857
An invertible ideal in a commutative ring with finitely many maximal ideals is principal.
https://math.stackexchange.com/a/95857
A Dedekind domain is a PID if its set of primes is finite.
If p
is a prime in the Dedekind domain R
, S
an extension of R
and Sₚ
the localization
of S
at p
, then all primes in Sₚ
are factors of the image of p
in Sₚ
.
Let p
be a prime in the Dedekind domain R
and S
be an integral extension of R
,
then the localization Sₚ
of S
at p
is a PID.